Given, parabola
y2=8x ...... (i)
Equation of tangent at P(2,−4) is
−4y=4(x+2)
or, x+y+2=0 ..... (ii)
and Equation of normal to the parabola is
x−y+C=0
∴ Normal passes through (2,−4)
∴ C=−6
Normal : x−y=6 ..... (iii)
Equation of directrix of parabola
x=−2 ..... (iv)
Point of intersection of tangent and normal with directrix are x=−2 at A(−2,0) and B(−2,−8) respectively.
Q(a,b) and P(2,−4) are given and AQBP is a square.
Mid-point of AB = Mid-point of PQ
⇒(−2,−4)=(2a+2,2b−4)⇒a=−6,b=−4
⇒2a+b=−16