Effective molality = 0.6 + 1.6 + 0.4 = 2.6 m
As elevation in boiling point is a colligative property which depends on the amount of solute. So, to have same boiling point, the molality of two solutions should be same.
Molality of non-electrolyte solution = molality of K4[Fe(CN)6] = 2.6 m
Now, 18.1 weight per cent solution means 18.1 g solute is present in 100 g solution and hence, (100 − 18.1) = 81.9 g water.
Molality=Massofsolventinkg(Massofsolute/Molarmassofsolute)×1000
Now, 2.6=81.9/100018.1/M
where, M is the molar mass of non-electrolyte solute
Molar mass of solute, M = 85