The star "*" in this context represents a binary operation, similar to addition (+), subtraction (-), multiplication (×), and division (÷). It is a custom operation defined by the problem statement, and the specific rules of the operation are provided in the problem.
In this case, the operation "*" is defined by the equation
x∗y=x2+y3, which means if you have two numbers
x and
y, then the result of applying the "*" operation to them is
x2+y3.
The problem also specifies an additional rule for this operation:
(x∗1)∗1=x∗(1∗1), which needs to be taken into account when solving the problem. This is a type of "associativity" condition.
Given,
x∗y=x2+y3
∴ x∗1=x2+13=x2+1
Now, (x∗1)∗1=(x2+1)∗1
⇒(x∗1)∗1=(x2+1)2+13
⇒(x∗1)∗1=x4+1+2x2+1
Also, x∗(1∗1)
=x∗(12+13)
=x∗2
=x2+23
=x2+8
Given that,
(x∗1)∗1=x∗(1∗1)
∴ x4+1+2x2+1=x2+8
⇒x4+x2−6=0
⇒x4+3x2−2x2−6=0
⇒x2(x2+3)−2(x3+3)=0
⇒(x2+3)(x2−2)=0
⇒x2=2,−3
[x2=−3 not possible as square of anything should be always positive]
∴ x2=2
∴ Now,
2sin−1(x4+x2+2x4+x2−2)
=2sin−1(22+2+222+2−2)
=2sin−1(84)
=2sin−1(21)
=2×6π
=3π