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Algebra
MathematicsAlgebraJEE Main & Advanced

Algebra Formulas

Complete chapter-wise formula sheet for Algebra (Mathematics) covering key equations, parameters, traps, and concept diagrams for JEE Main & Advanced.

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Chapter Directory (26 Chapters)

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Formulas Reference (Algebra)

8 Chapters match
AlgebraTop Priority (3-4 Qs in JEE)1,015 PYQs

Matrices & Determinants

Matrix algebra, determinant expansion, adjoint properties, inverse, Cramer's rule, and systems of linear equations.

Determinant Properties

∣AT∣=∣A∣,∣AB∣=∣A∣∣B∣,∣kA∣=kn∣A∣(n×n matrix)|A^T| = |A|, \quad |AB| = |A||B|, \quad |kA| = k^n |A| \quad (n \times n \text{ matrix})

Scalar multiplication pulls out factor k raised to the dimension power n.

|A⁻¹| = 1 / |A|.

Adjoint Properties

A⋅adj(A)=∣A∣In,∣adj(A)∣=∣A∣n−1,∣adj(adj(A))∣=∣A∣(n−1)2A \cdot \text{adj}(A) = |A| I_n, \quad |\text{adj}(A)| = |A|^{n-1}, \quad |\text{adj}(\text{adj}(A))| = |A|^{(n-1)^2}

Crucial adjoint determinant power formulas tested almost every year in JEE Main.

For 3x3 matrix (n = 3): |adj(A)| = |A|² and |adj(adj(A))| = |A|⁴.

Matrix Inverse Formula

A−1=1∣A∣adj(A)(∣A∣≠0)A^{-1} = \frac{1}{|A|} \text{adj}(A) \quad (|A| \ne 0)

Inverse exists if and only if matrix A is non-singular (|A| ≠ 0).

(AB)⁻¹ = B⁻¹ A⁻¹ (reversal law).

Cramer's Rule for Linear Systems

x=ΔxΔ,y=ΔyΔ,z=ΔzΔx = \frac{\Delta_x}{\Delta}, \quad y = \frac{\Delta_y}{\Delta}, \quad z = \frac{\Delta_z}{\Delta}

Determinant method for solving system of linear equations.

Δ ≠ 0: Unique solution. Δ = 0 with any Δ_i ≠ 0: Inconsistent (No solution).

Symmetric & Skew-Symmetric Matrices

A=A+AT2+A−AT2,Skew-Symmetric: AT=−A  ⟹  aii=0A = \frac{A + A^T}{2} + \frac{A - A^T}{2}, \quad \text{Skew-Symmetric: } A^T = -A \implies a_{ii} = 0

Every square matrix is uniquely decomposable into symmetric and skew-symmetric parts.

Determinant of odd-order skew-symmetric matrix is ALWAYS zero.

Orthogonal Matrix Property

A⋅AT=I  ⟹  ∣A∣=±1,A−1=ATA \cdot A^T = I \implies |A| = \pm 1, \quad A^{-1} = A^T

Orthogonal matrices preserve lengths and angles.

Rows and columns form orthonormal vectors.

Cayley-Hamilton Theorem & Matrix Powers

det⁡(A−λI)=0  ⟹  P(A)=O,A2−tr(A)A+∣A∣I=O  (2×2)\det(A - \lambda I) = 0 \implies P(A) = O, \quad A^2 - \text{tr}(A)A + |A|I = O \; (2 \times 2)

Every square matrix satisfies its own characteristic polynomial equation. Enables computing high powers and inverses.

To find A⁻¹, multiply the characteristic equation throughout by A⁻¹.

Special Matrix Types (Idempotent, Involutory, Nilpotent)

A2=A  (Idempotent),A2=I  (Involutory),Ak=O  (Nilpotent),tr(AB)=tr(BA)A^2 = A \; (\text{Idempotent}), \quad A^2 = I \; (\text{Involutory}), \quad A^k = O \; (\text{Nilpotent}), \quad \text{tr}(AB) = \text{tr}(BA)

Key algebraic matrix classes frequently tested in eigenvalue and matrix polynomial questions.

Eigenvalues of idempotent matrices can only be 0 or 1. Determinant of involutory matrix is ±1.

Homogeneous System of Linear Equations (AX = 0)

∣A∣≠0  ⟹  X=O  (Trivial Unique Solution),∣A∣=0  ⟹  Infinitely Many Non-Trivial Solutions|A| \ne 0 \implies X = O \; (\text{Trivial Unique Solution}), \quad |A| = 0 \implies \text{Infinitely Many Non-Trivial Solutions}

Criterion for existence of non-zero solutions to homogeneous linear equations.

If a homogeneous system has a non-trivial solution, its determinant MUST equal 0.
AlgebraHigh Yield (2-3 Qs in JEE)1,001 PYQs

Probability & Distributions

Conditional probability, Bayes theorem, independent events, total probability, and binomial distribution.

Conditional Probability

P(A∣B)=P(A∩B)P(B)(P(B)>0)P(A|B) = \frac{P(A \cap B)}{P(B)} \quad (P(B) > 0)

Probability of event A occurring given that B has already occurred.

If events are independent, P(A|B) = P(A).

Bayes' Theorem

P(Ei∣A)=P(Ei)P(A∣Ei)∑j=1nP(Ej)P(A∣Ej)P(E_i|A) = \frac{P(E_i) P(A|E_i)}{\sum_{j=1}^n P(E_j) P(A|E_j)}

Calculates reverse (posterior) probability using total probability denominator.

Write partition events E₁, E₂... clearly before evaluating branch likelihoods.

Binomial Distribution (Mean & Variance)

P(X=r)=nCrprqn−r,Mean μ=np,Variance σ2=npqP(X = r) = {}^nC_r p^r q^{n-r}, \quad \text{Mean } \mu = np, \quad \text{Variance } \sigma^2 = npq

Probability distribution for r successes in n independent Bernoulli trials (p + q = 1).

Variance is ALWAYS strictly less than Mean for Binomial distributions (npq < np since q < 1).

Total Probability Theorem

P(A)=∑i=1nP(Ei)⋅P(A∣Ei)P(A) = \sum_{i=1}^n P(E_i) \cdot P(A|E_i)

Law of total probability over a partition of sample space.

Forms the denominator of Bayes theorem.

Addition Theorem & 3-Event Inclusion-Exclusion

P(A∪B∪C)=P(A)+P(B)+P(C)−P(AB)−P(BC)−P(CA)+P(ABC)P(A \cup B \cup C) = P(A) + P(B) + P(C) - P(AB) - P(BC) - P(CA) + P(ABC)

Probability of occurrence of at least one of three arbitrary events.

Probability of exactly two events occurring = P(AB) + P(BC) + P(CA) - 3 P(ABC).

Odds in Favor & Odds Against

Odds in favor of A=P(A)P(A′)=mn  ⟹  P(A)=mm+n,Odds against =nm\text{Odds in favor of } A = \frac{P(A)}{P(A')} = \frac{m}{n} \implies P(A) = \frac{m}{m + n}, \quad \text{Odds against } = \frac{n}{m}

Ratio of favorable outcomes to unfavorable outcomes.

If odds in favor of an event are 3:5, its probability is 3/(3 + 5) = 3/8.

Expectation & Variance of Discrete Random Variable

E(X)=∑xipi,Var(X)=E(X2)−[E(X)]2=∑xi2pi−μ2,Var(aX+b)=a2Var(X)E(X) = \sum x_i p_i, \quad \text{Var}(X) = E(X^2) - [E(X)]^2 = \sum x_i^2 p_i - \mu^2, \quad \text{Var}(aX + b) = a^2 \text{Var}(X)

Mathematical expectation (weighted mean) and spread of a discrete probability distribution.

E(aX + b) = a E(X) + b. For independent random variables X and Y: Var(X ± Y) = Var(X) + Var(Y).
AlgebraVery High Yield (2-3 Qs in JEE)658 PYQs

Complex Numbers

Argand plane, polar & Euler forms, triangle inequalities, cube roots of unity, De Moivre's theorem, and geometric loci.

Polar & Euler Form

z=x+iy=r(cos⁡θ+isin⁡θ)=reiθ(r=∣z∣=x2+y2,  θ=arg⁡(z))z = x + iy = r(\cos\theta + i\sin\theta) = r e^{i\theta} \quad (r = |z| = \sqrt{x^2 + y^2}, \; \theta = \arg(z))

Exponential Euler representation for complex numbers.

e^(iπ) + 1 = 0 (Euler's identity).

Triangle Inequalities

∣∣z1∣−∣z2∣∣≤∣z1±z2∣≤∣z1∣+∣z2∣||z_1| - |z_2|| \le |z_1 \pm z_2| \le |z_1| + |z_2|

Bounds for modulus of sum and difference of complex numbers.

Equality holds when origin, z₁, and z₂ are collinear.

Cube Roots of Unity (1, ω, ω²)

1+ω+ω2=0,ω3=1,ω=−1+i32=ei2π/31 + \omega + \omega^2 = 0, \quad \omega^3 = 1, \quad \omega = \frac{-1 + i\sqrt{3}}{2} = e^{i 2\pi/3}

Roots of equation z³ - 1 = 0.

1 + ω^n + ω^(2n) = 3 if n is multiple of 3, else 0.

De Moivre's Theorem

(cos⁡θ+isin⁡θ)n=cos⁡(nθ)+isin⁡(nθ)=einθ(\cos\theta + i\sin\theta)^n = \cos(n\theta) + i\sin(n\theta) = e^{in\theta}

Powers and roots of trigonometric complex forms for integer and rational n.

Always convert to polar form before taking high powers like z²⁰²⁴.

Geometric Locus in Complex Plane

∣z−z0∣=r  (Circle),∣z−z1∣=∣z−z2∣  (Perpendicular Bisector),arg⁡(z−z1z−z2)=θ  (Circular Arc)|z - z_0| = r \; (\text{Circle}), \quad |z - z_1| = |z - z_2| \; (\text{Perpendicular Bisector}), \quad \arg\left(\frac{z - z_1}{z - z_2}\right) = \theta \; (\text{Circular Arc})

Translating complex equations into 2D Cartesian geometric figures.

If θ = ±π/2, the locus is a circle with z₁ and z₂ as diametric endpoints.

Rotation Theorem (Coni's Theorem)

z3−z1z2−z1=∣z3−z1∣∣z2−z1∣eiα\frac{z_3 - z_1}{z_2 - z_1} = \frac{|z_3 - z_1|}{|z_2 - z_1|} e^{i\alpha}

Rotates directed line segment (z₂ - z₁) by an angle α counter-clockwise around pivot point z₁ to obtain direction of (z₃ - z₁).

For an equilateral triangle with vertices z₁, z₂, z₃: z₁² + z₂² + z₃² = z₁z₂ + z₂z₃ + z₃z₁.

Apollonius Circle & Conic Loci in Argand Plane

∣z−z1∣∣z−z2∣=k  (k≠1  ⟹  Circle),∣z−z1∣+∣z−z2∣=2a  (2a>∣z1−z2∣  ⟹  Ellipse)\frac{|z - z_1|}{|z - z_2|} = k \; (k \ne 1 \implies \text{Circle}), \quad |z - z_1| + |z - z_2| = 2a \; (2a > |z_1 - z_2| \implies \text{Ellipse})

Modulus ratio represents an Apollonius circle, while sum and difference of distances represent ellipses and hyperbolas.

If |z - z₁| + |z - z₂| = |z₁ - z₂|, locus is the line segment joining z₁ and z₂.

n-th Roots of Unity & Factorization

zn=1  ⟹  zk=ei2kπn(k=0,1,…,n−1),∑k=0n−1zk=0,∏k=0n−1zk=(−1)n−1z^n = 1 \implies z_k = e^{i \frac{2k\pi}{n}} \quad (k = 0, 1, \dots, n-1), \quad \sum_{k=0}^{n-1} z_k = 0, \quad \prod_{k=0}^{n-1} z_k = (-1)^{n-1}

The n-th roots of unity form vertices of a regular n-gon inscribed in unit circle centered at origin.

Factorization identity: x^n - 1 = (x - 1)(x - α)(x - α²) ... (x - α^(n-1)).
AlgebraHigh Yield (2 Qs in JEE)599 PYQs

Permutations & Combinations (P&C)

Fundamental principle of counting, nPr, nCr, circular permutations, distribution into groups, and de-arrangement.

Basic Permutation & Combination Formulas

nPr=n!(n−r)!,nCr=n!r!(n−r)!,nCr+nCr−1=n+1Cr{}^nP_r = \frac{n!}{(n-r)!}, \quad {}^nC_r = \frac{n!}{r!(n-r)!}, \quad {}^nC_r + {}^nC_{r-1} = {}^{n+1}C_r

Fundamental counting formulas (Pascal's rule).

^nC_r = ^nC_{n-r}.

Number of Non-Negative Integral Solutions

x1+x2+⋯+xr=n  ⟹  Solutions=n+r−1Cr−1x_1 + x_2 + \dots + x_r = n \implies \text{Solutions} = {}^{n + r - 1}C_{r - 1}

Stars and bars method: distributing n identical items into r distinct boxes.

For positive integral solutions (x_i ≥ 1), solutions = ^{n - 1}C_{r - 1}.

De-arrangement Formula (D_n)

Dn=n![1−11!+12!−13!+⋯+(−1)nn!]D_n = n! \left[ 1 - \frac{1}{1!} + \frac{1}{2!} - \frac{1}{3!} + \dots + \frac{(-1)^n}{n!} \right]

Number of permutations such that none of the n objects appear in their original natural position.

D₁ = 0, D₂ = 1, D₃ = 2, D₄ = 9, D₅ = 44.

Division into Groups

Equal Groups: (mn)!(m!)nn!,Unequal Groups: (m+n+p)!m!n!p!\text{Equal Groups: } \frac{(mn)!}{(m!)^n n!}, \quad \text{Unequal Groups: } \frac{(m+n+p)!}{m! n! p!}

Formulas for partition into distinct or identical sets.

Divide by k! whenever k groups have the same size and are undistinguished.

Circular Permutations & Necklaces

Pcircle=(n−1)!,Pnecklace=(n−1)!2P_{\text{circle}} = (n - 1)!, \quad P_{\text{necklace}} = \frac{(n - 1)!}{2}

Arrangements around a round table versus a necklace/garland where flip-over (clockwise = anticlockwise) makes halves identical.

If arranging n men and n women alternatively around a round table: (n - 1)! × n!.

Grid / Lattice Path Counting

Paths from (0,0)→(m,n)=(m+n)!m!n!=m+nCm\text{Paths from } (0, 0) \to (m, n) = \frac{(m + n)!}{m! n!} = {}^{m+n}C_m

Number of shortest monotonic paths on an m × n grid moving only rightward (R) and upward (U).

If passing through an intermediate point (p, q): Total Paths = {}^{p+q}C_p × {}^{(m-p)+(n-q)}C_{m-p}.

Distribution of Distinct Objects into Boxes

rn  (Distinct items, Distinct boxes),∑k=0r(−1)r−krCkkn  (No empty box)r^n \; (\text{Distinct items, Distinct boxes}), \quad \sum_{k=0}^r (-1)^{r-k} {}^rC_k k^n \; (\text{No empty box})

Fundamental distribution theorem with restrictions on empty containers using inclusion-exclusion.

Total number of functions from set of n elements to set of r elements is r^n; total onto functions is r! · S(n, r).
AlgebraHigh Yield (2-3 Qs in JEE)551 PYQs

Sequences & Series

Arithmetic, geometric, arithmetico-geometric (AGP), harmonic progressions, AM-GM-HM inequality, and telescoping series.

Arithmetic Progression (AP)

Tn=a+(n−1)d,Sn=n2[2a+(n−1)d]=n2(a+l)T_n = a + (n - 1)d, \quad S_n = \frac{n}{2}[2a + (n - 1)d] = \frac{n}{2}(a + l)

Standard formulas for linear progressions.

Three terms in AP are best assumed as (a - d, a, a + d).

Geometric Progression (GP)

Tn=arn−1,Sn=a(1−rn)1−r,S∞=a1−r(∣r∣<1)T_n = a r^{n-1}, \quad S_n = \frac{a(1 - r^n)}{1 - r}, \quad S_\infty = \frac{a}{1 - r} \quad (|r| < 1)

Exponential series with common ratio r.

Three terms in GP are best assumed as (a/r, a, ar).

AM-GM-HM Inequality

a+b2≥ab≥2aba+b  ⟺  AM≥GM≥HM\frac{a + b}{2} \ge \sqrt{ab} \ge \frac{2ab}{a + b} \iff \text{AM} \ge \text{GM} \ge \text{HM}

Fundamental algebraic inequality for positive real numbers. Equality holds iff all terms are equal.

Premier tool for finding minimum values of expressions like x + 1/x ≥ 2.

Sum of First n Powers of Natural Numbers

∑n=n(n+1)2,∑n2=n(n+1)(2n+1)6,∑n3=[n(n+1)2]2\sum n = \frac{n(n+1)}{2}, \quad \sum n^2 = \frac{n(n+1)(2n+1)}{6}, \quad \sum n^3 = \left[\frac{n(n+1)}{2}\right]^2

Standard power sum formulas for polynomial series evaluation.

Notice that ∑ n³ = (∑ n)².

Arithmetico-Geometric Progression (AGP) Sums

S∞=a1−r+d⋅r(1−r)2,Sn=a1−r+dr(1−rn−1)(1−r)2−[a+(n−1)d]rn1−rS_\infty = \frac{a}{1 - r} + \frac{d \cdot r}{(1 - r)^2}, \quad S_n = \frac{a}{1 - r} + \frac{d r(1 - r^{n-1})}{(1 - r)^2} - \frac{[a + (n-1)d]r^n}{1 - r}

Sum of finite and infinite series whose terms are products of an AP and a GP.

To evaluate manually: multiply by r and subtract (1 - r)S = a + d·r + d·r² + ... - [a + (n-1)d]r^n.

Method of Differences & Telescoping Series

Sn=∑r=1n[f(r)−f(r−1)]=f(n)−f(0),1r(r+1)(r+2)=12[1r(r+1)−1(r+1)(r+2)]S_n = \sum_{r=1}^n [f(r) - f(r-1)] = f(n) - f(0), \quad \frac{1}{r(r+1)(r+2)} = \frac{1}{2}\left[\frac{1}{r(r+1)} - \frac{1}{(r+1)(r+2)}\right]

Splitting general term T_r into difference of consecutive functions cancels all intermediate terms.

For products of factors in AP in the denominator: multiply and divide by (last factor - first factor).

Cauchy-Schwarz & Weighted AM-GM Inequalities

(∑ai2)(∑bi2)≥(∑aibi)2,∑mixi∑mi≥(∏ximi)1∑mi(\sum a_i^2)(\sum b_i^2) \ge (\sum a_i b_i)^2, \quad \frac{\sum m_i x_i}{\sum m_i} \ge \left(\prod x_i^{m_i}\right)^{\frac{1}{\sum m_i}}

Powerful analytical inequalities for finding minimum values of multivariable constrained expressions in JEE Advanced.

Equality holds in Cauchy-Schwarz iff a₁/b₁ = a₂/b₂ = ... = a_n/b_n.

Harmonic Progression (HP) & Relation Between Means

H=2aba+b,G2=A⋅H,A≥G≥H(a,b>0)H = \frac{2ab}{a+b}, \quad G^2 = A \cdot H, \quad A \ge G \ge H \quad (a, b > 0)

Sequence whose reciprocals form an AP. Geometric mean is the geometric mean between AM and HM.

There is no general summation formula for HP series; solve HP problems by converting terms to AP reciprocals.
AlgebraHigh Yield (2 Qs in JEE)443 PYQs

Binomial Theorem

General term T_{r+1}, middle term, greatest term, binomial coefficients identities, and remainder theorem.

General Term in Binomial Expansion

(x+y)n=∑r=0nnCrxn−ryr,Tr+1=nCrxn−ryr(x + y)^n = \sum_{r=0}^n {}^nC_r x^{n-r} y^r, \quad T_{r+1} = {}^nC_r x^{n-r} y^r

Expansion has (n + 1) terms.

Independent of x term occurs when power of x in T_{r+1} equals 0.

Binomial Coefficient Sum Identities

∑r=0nnCr=2n,∑r=0n(−1)rnCr=0,∑r=1nr⋅nCr=n⋅2n−1\sum_{r=0}^n {}^nC_r = 2^n, \quad \sum_{r=0}^n (-1)^r {}^nC_r = 0, \quad \sum_{r=1}^n r \cdot {}^nC_r = n \cdot 2^{n-1}

Classic combinatorial summation identities.

Differentiate (1 + x)^n to find sums with r in the coefficient.

Middle Term in Expansion

n even  ⟹  Tn2+1;n odd  ⟹  Tn+12 and Tn+32n \text{ even} \implies T_{\frac{n}{2} + 1}; \quad n \text{ odd} \implies T_{\frac{n+1}{2}} \text{ and } T_{\frac{n+3}{2}}

Has the greatest binomial coefficient ^nC_{max}.

For even n, single middle term has maximum coefficient ^nC_{n/2}.

Fractional / Negative Index Binomial Series

(1+x)n=1+nx+n(n−1)2!x2+n(n−1)(n−2)3!x3+⋯(∣x∣<1),Tr+1=n(n−1)⋯(n−r+1)r!xr(1 + x)^n = 1 + nx + \frac{n(n-1)}{2!}x^2 + \frac{n(n-1)(n-2)}{3!}x^3 + \cdots \quad (|x| < 1), \quad T_{r+1} = \frac{n(n-1)\cdots(n-r+1)}{r!}x^r

Infinite convergent series for any rational n (negative or fractional). General term uses falling factorial in numerator.

Common cases: (1+x)^{-1} = 1 - x + x² - x³ + ⋯, (1-x)^{-1} = 1 + x + x² + x³ + ⋯, (1+x)^{-2} = 1 - 2x + 3x² - 4x³ + ⋯. All valid for |x| < 1.

Weighted Binomial Coefficient Sums

∑r=1nr⋅nCr=n⋅2n−1,∑r=1nr2⋅nCr=n(n+1)⋅2n−2,∑r=0n1r+1nCr=2n+1−1n+1\sum_{r=1}^n r \cdot {}^nC_r = n \cdot 2^{n-1}, \quad \sum_{r=1}^n r^2 \cdot {}^nC_r = n(n+1) \cdot 2^{n-2}, \quad \sum_{r=0}^n \frac{1}{r+1}{}^nC_r = \frac{2^{n+1} - 1}{n + 1}

Weighted sums obtained by differentiating or integrating (1+x)^n and substituting x = 1.

Differentiate (1+x)^n once → Σ r·C(n,r)·x^(r-1); differentiate again → Σ r(r-1)·C(n,r)·x^(r-2). Add to get r²·C(n,r) sum.

Multinomial Theorem & Number of Terms

(x1+x2+⋯+xk)n=∑n!r1!r2!…rk!x1r1x2r2…xkrk,Total Terms=n+k−1Ck−1(x_1 + x_2 + \dots + x_k)^n = \sum \frac{n!}{r_1! r_2! \dots r_k!} x_1^{r_1} x_2^{r_2} \dots x_k^{r_k}, \quad \text{Total Terms} = {}^{n+k-1}C_{k-1}

Expansion of sum of k variables raised to integer power n where r₁ + r₂ + ... + r_k = n.

Coefficient of x₁^{r₁} x₂^{r₂}...x_k^{r_k} is the multinomial coefficient n! / (r₁! r₂!...r_k!).

Numerically Greatest Term (NGT)

∣Tr+1Tr∣=n−r+1r∣yx∣≥1  ⟹  r≤n+11+∣x/y∣\left| \frac{T_{r+1}}{T_r} \right| = \frac{n - r + 1}{r} \left| \frac{y}{x} \right| \ge 1 \implies r \le \frac{n + 1}{1 + |x/y|}

Determines the term having the largest magnitude in the expansion of (x + y)^n.

If m = (n+1)/(1 + |x/y|) is an integer, both T_m and T_{m+1} are equal and numerically greatest.

Divisibility & Remainder Finding

(1+k)n=1+nk+nC2k2+⋯≡1+nk(modk2)(1 + k)^n = 1 + nk + {^nC_2} k^2 + \dots \equiv 1 + nk \pmod{k^2}

Express base as (multiple of divisor ± remainder) to find remainders of large powers.

For finding remainder of 7¹⁰³ divided by 25: rewrite as 7 · (49)⁵¹ = 7 · (50 - 1)⁵¹.
AlgebraHigh Yield (1-2 Qs in JEE)315 PYQs

Quadratic Equations

Roots of quadratic, discriminant nature, Vieta relations, condition for common roots, and location of roots.

Quadratic Formula & Vieta's Relations

x=−b±b2−4ac2a,α+β=−ba,αβ=cax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, \quad \alpha + \beta = -\frac{b}{a}, \quad \alpha\beta = \frac{c}{a}

Roots and coefficients of ax² + bx + c = 0.

Difference of roots: |α - β| = √(D) / |a|.

Nature of Roots & Discriminant D

D=b2−4ac:D>0  (Real, Distinct),D=0  (Real, Equal),D<0  (Complex Conjugates)D = b^2 - 4ac: \quad D > 0 \; (\text{Real, Distinct}), \quad D = 0 \; (\text{Real, Equal}), \quad D < 0 \; (\text{Complex Conjugates})

Discriminant determines the geometric intersection with the x-axis.

If a, b, c are rational and D is not a perfect square, roots occur in irrational conjugate pairs (p ± √q).

Location of Roots (Both Roots > k)

D≥0,−b2a>k,a⋅f(k)>0D \ge 0, \quad -\frac{b}{2a} > k, \quad a \cdot f(k) > 0

Simultaneous necessary and sufficient conditions for both roots to lie to the right of value k.

If roots lie on opposite sides of k, the ONLY condition needed is a * f(k) < 0.

Condition for Both Roots Common

a1a2=b1b2=c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}

Condition for two quadratic equations to have identical solutions.

If one equation has imaginary roots (D < 0), having ONE common root implies BOTH roots are common.

Condition for Exactly One Common Root

(c1a2−c2a1)2=(a1b2−a2b1)(b1c2−b2c1),x=c1a2−c2a1a1b2−a2b1(c_1 a_2 - c_2 a_1)^2 = (a_1 b_2 - a_2 b_1)(b_1 c_2 - b_2 c_1), \quad x = \frac{c_1 a_2 - c_2 a_1}{a_1 b_2 - a_2 b_1}

Cross-multiplication determinant condition for a single shared root between two quadratics.

The common root can also be found directly by subtracting equations to eliminate the x² term.

Newton's Sum Theorem for Polynomial Roots

Sn=αn+βn  ⟹  aSn+bSn−1+cSn−2=0S_n = \alpha^n + \beta^n \implies a S_n + b S_{n-1} + c S_{n-2} = 0

Powerful recurrence relation connecting powers of roots for ax² + bx + c = 0.

Very frequent in JEE Main: e.g. finding (a₁₀ - 2a₈) / 2a₉ without solving for roots explicitly.

Transformation of Quadratic Equations

Roots kα,kβ  ⟹  a(x/k)2+b(x/k)+c=0;Roots 1/α,1/β  ⟹  cx2+bx+a=0;Roots α±h  ⟹  a(x∓h)2+b(x∓h)+c=0\text{Roots } k\alpha, k\beta \implies a(x/k)^2 + b(x/k) + c = 0; \quad \text{Roots } 1/\alpha, 1/\beta \implies c x^2 + b x + a = 0; \quad \text{Roots } \alpha \pm h \implies a(x \mp h)^2 + b(x \mp h) + c = 0

Symmetric transformations of equations without recalculating individual roots.

For roots α² and β², substitute x = √y and square to eliminate radicals.
AlgebraHigh Yield (1-2 Qs in JEE)332 PYQs

Statistics

Mean, variance, standard deviation, mean deviation, and effect of linear change of origin and scale.

Mean & Variance Formulas

xˉ=∑xin,σ2=∑xi2n−(xˉ)2=∑(xi−xˉ)2n\bar{x} = \frac{\sum x_i}{n}, \quad \sigma^2 = \frac{\sum x_i^2}{n} - (\bar{x})^2 = \frac{\sum (x_i - \bar{x})^2}{n}

Measures of central tendency and dispersion.

Variance = (Mean of squares) - (Square of mean).

Change of Origin and Scale

yi=axi+b  ⟹  yˉ=axˉ+b,σy2=a2σx2,σy=∣a∣σxy_i = a x_i + b \implies \bar{y} = a\bar{x} + b, \quad \sigma_y^2 = a^2 \sigma_x^2, \quad \sigma_y = |a| \sigma_x

Shift of origin (b) does not affect variance or standard deviation.

Adding constant to every observation leaves variance completely unchanged.

Combined Mean & Variance

xˉ12=n1xˉ1+n2xˉ2n1+n2,σ122=n1(σ12+d12)+n2(σ22+d22)n1+n2(di=xˉi−xˉ12)\bar{x}_{12} = \frac{n_1 \bar{x}_1 + n_2 \bar{x}_2}{n_1 + n_2}, \quad \sigma_{12}^2 = \frac{n_1(\sigma_1^2 + d_1^2) + n_2(\sigma_2^2 + d_2^2)}{n_1 + n_2} \quad (d_i = \bar{x}_i - \bar{x}_{12})

Pooled variance of two combined statistical groups.

Standard deviation cannot be simply averaged.

Mean Deviation about Mean & Median

MD(xˉ)=∑∣xi−xˉ∣n,MD(M)=∑∣xi−M∣nMD(\bar{x}) = \frac{\sum |x_i - \bar{x}|}{n}, \quad MD(M) = \frac{\sum |x_i - M|}{n}

Mean absolute dispersion of observations from central tendency. Mean deviation is strictly MINIMUM when measured about the Median.

Coefficient of MD = (Mean Deviation) / (Mean or Median).

Coefficient of Variation (C.V.) & Consistency

C.V.=σxˉ×100%\text{C.V.} = \frac{\sigma}{\bar{x}} \times 100\%

Relative measure of dispersion used to compare consistency between two datasets.

The series or team with smaller C.V. is considered more consistent and uniform.

Mean & Variance of First n Natural Numbers

xˉ=n+12,σ2=n2−112,σ=n2−112\bar{x} = \frac{n + 1}{2}, \quad \sigma^2 = \frac{n^2 - 1}{12}, \quad \sigma = \sqrt{\frac{n^2 - 1}{12}}

Direct closed-form results for arithmetic mean and variance of first n positive integers {1, 2, ..., n}.

Frequently asked direct question in JEE Main (e.g. variance of first 50 natural numbers is (2500 - 1)/12 = 208.25).

Empirical Relation of Central Tendencies

Mode=3 Median−2 Mean  ⟺  Mean−Mode=3(Mean−Median)\text{Mode} = 3\,\text{Median} - 2\,\text{Mean} \iff \text{Mean} - \text{Mode} = 3(\text{Mean} - \text{Median})

Karl Pearson's empirical formula connecting mean, median, and mode for moderately skewed unimodal frequency distributions.

For perfectly symmetrical distribution, Mean = Median = Mode.

Variance of First n Even & Odd Numbers

Even {2,4,…,2n}:xˉ=n+1,  σ2=n2−13;Odd {1,3,…,2n−1}:xˉ=n,  σ2=n2−13\text{Even } \{2, 4, \dots, 2n\}: \bar{x} = n + 1, \; \sigma^2 = \frac{n^2 - 1}{3}; \quad \text{Odd } \{1, 3, \dots, 2n-1\}: \bar{x} = n, \; \sigma^2 = \frac{n^2 - 1}{3}

Variance of first n consecutive even and odd positive integers.

Notice that variance of first n even numbers and first n odd numbers is identical: (n² - 1)/3.